y^-1/2=1/(12-x^2)

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Solution for y^-1/2=1/(12-x^2) equation: 


D( x )

12-x^2 = 0

12-x^2 = 0

12-x^2 = 0

-1*x^2 = -12 // : -1

x^2 = 12

x^2 = 12 // ^ 1/2

abs(x) = 2*3^(1/2)

x = 2*3^(1/2) or x = -(2*3^(1/2))

x in (-oo:-(2*3^(1/2))) U (-(2*3^(1/2)):2*3^(1/2)) U (2*3^(1/2):+oo)

(y^-1)/2 = 1/(12-x^2) // - 1/(12-x^2)

(y^-1)/2-(1/(12-x^2)) = 0

(y^-1)/2-(12-x^2)^-1 = 0

1/(2*y)-1/(12-x^2) = 0

(-1*2*y)/(2*y*(12-x^2))+(1*(12-x^2))/(2*y*(12-x^2)) = 0

1*(12-x^2)-1*2*y = 0

12-x^2-2*y = 0

(12-x^2-2*y)/(2*y*(12-x^2)) = 0

(12-x^2-2*y)/(2*y*(12-x^2)) = 0 // * 2*y*(12-x^2)

12-x^2-2*y = 0

-1*x^2 = -(12-2*y) // : -1

x^2 = 12-2*y

x^2 = 12-2*y // ^ 1/2

abs(x) = (12-2*y)^(1/2)

x = (12-2*y)^(1/2) or x = -(12-2*y)^(1/2)

x in { (12-2*y)^(1/2), -(12-2*y)^(1/2) }

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